Christian Hennig wrote:
Hi,
I want to do something like this:
par(mfrow=c(7,7)) for (i in 1:49) hist(RATDACOM[SUBJNO==i],breaks=0.5+(0:6), main="",xlab="",ylab="",xaxt="n",yaxt="n")
(Don't think about what RATDACOM and SUBJNO are.)
I get an error Error in plot.new() : Figure margins too large.
36 histograms with mfrow=c(6,6) work. But the 36 histograms are then so small that I wonder why 49 do not fit. It seems that though I have main="",xlab="",ylab="",xaxt="n",yaxt="n" the area reserved for axes and labels is almost as large as it would be if I would print a single histogram. The histogram itself only gets the remaining space, which is very small (I could draw 36*4 histograms of this size on a single page and the margins between them would still be OK).
So the question is: How do I tell R to print the essential histogram area without main, labs and axes large enough that it looks well but small enough that 49 fit on one page? (If I would draw them by hand, no problem...)
Best, Christian
You may want to look at ?histogram in package:lattice.
set.seed(1)
m <- 100
n <- 49
RATDACOM <- rnorm(m * n)
SUBJNO <- rep(seq(n), each = m)
histogram(~ RATDACOM | SUBJNO,
layout = c(7, 7),
strip = FALSE)--sundar
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