On Wed, 2 Mar 2005 12:13:17 +0000, "Jan T. Kim" <[EMAIL PROTECTED]>
wrote :
>On Tue, Mar 01, 2005 at 11:21:44PM -0800, Seth Falcon wrote:
>> On Feb 25, 2005, at 12:34 PM, [EMAIL PROTECTED] wrote:
>>
>> >Is is possible from within a function to cause its caller to return()?
>>
>> This snippet may be of interest:
>>
>>
>> > f = function(x) {
>> + print("f")
>> + g(return())
>> + print("end of f")
>> + }
>>
>> > g=function(x) {print("g")
>> + x
>> + print("end of g")
>> + }
>>
>> > f(1)
>> [1] "f"
>> [1] "g"
>> NULL
>
>I may be dumb today, but doesn't that beg the question of how does g
>cause f not to return?
I'm not suggesting that I would ever use code like this, but if x is
never evaluated then the double return would not happen:
> f
function(x) {
print("f")
g(x, return())
print("end of f")
}
> g
function(x, blastoff) {
print("g")
if (x) blastoff
print("end of g")
}
> f(TRUE)
[1] "f"
[1] "g"
NULL
> f(FALSE)
[1] "f"
[1] "g"
[1] "end of g"
[1] "end of f"
However, this is not a style of programming that I would expect to
last for more than 5 minutes after I published a program using it.
Follow Thomas's advice, and use tryCatch instead.
Duncan Murdoch
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