Roy Werkman wrote:
Yes, it is discrete, but the underlying distribution is Gaussian.
/ I guess you mean what somebody calls the superpopulation distribution.
Kjetil
/
Just got the following from a college:
Var(mean of finite population) = ((N - n)/(N - 1)) * var(population) / n
This should be it...
Greetings,
Roy
-----Original Message-----
From: Liaw, Andy [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 23, 2005 2:17 PM
To: Roy Werkman; r-help@stat.math.ethz.ch
Subject: RE: [R] Question on statistics
If the sample is drawn with replacement from the finite population, then
the usual formula applies (assuming iid samples); i.e., var(sample mean)
=
var(population) / n.
There's some problem in your description: A finite population, I
believe, is necessarily discrete (since there are only N possible
values), so it can not be Gaussian (i.e., normal).
Andy
From: Roy Werkman
Ehh, by limited distribution, I meant to say a population of N points.
...
Hi,
Can anyone help me with the following (although not directly
correlated to R functionality)? I have been looking on the internet
but can not find the answer.
My question: what is the variation on the mean of a limited
distribution (total N points normally distributed), when I have a
small sample of that distribution (n < N)?
Your help would be very welcome.
Thanx,
Roy
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