you should look at the 'na.rm=FALSE' argument of '?mean()', i.e.,
x <- rnorm(100); x[sample(100, 10)] <- NA f <- sample(letters[1:5], 100, TRUE) ############### tapply(x, f, mean) tapply(x, f, mean, na.rm=TRUE)
I hope it helps.
Best, Dimitris
---- Dimitris Rizopoulos Ph.D. Student Biostatistical Centre School of Public Health Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +32/16/336899 Fax: +32/16/337015 Web: http://www.med.kuleuven.ac.be/biostat/ http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm
----- Original Message ----- From: "Leonardo Lami" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Friday, March 25, 2005 10:35 AM
Subject: [R] tapply and NA value
Hi,
I'm writing for a little help.
I have a dataframe with same NA value and I'd like to obtain the means of the
value of a coloumn grouped by the levels of a factor coloumn of the datframe.
I'm using the function "tapply" but I see that if only a NA value is present
the result is NA.
There is an option to have the correct result or I must use an other function?
Thanks of all
Leonardo
--
Leonardo Lami
[EMAIL PROTECTED] www.faunalia.it
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