>>>>> "simon" == simon chou <[EMAIL PROTECTED]>
>>>>> on Thu, 21 Apr 2005 18:36:17 +0800 writes:
simon> Hi, First ,please excuse my poor English.
no problem - we have read much worse ;-)
<...........>
simon> Another way I have tried uses .Fortran (). The fortran code were.
simon> 1.f
simon> subroutine readmm5(mm5file,IFLAG,MIF)
simon> integer iflag,MIF(50,20),MRF(20,20)
simon> CHARACTER*80 mm5file,MIFC(50,20),MRFC(20,20)
simon> OPEN (11,FILE=mm5file,FORM='UNFORMATTED')
simon> READ(11) IFLAG
simon> IF ( IFLAG .EQ. 0 ) THEN
simon> READ(mm5file) MIF,RMRF,MIFC,MRFC
simon> endif
simon> end
simon> $R CMD SHLIB 1.f
simon> $R
>> library(foreign)
>> dyn.load("1.so")
>>
.Fortran("readmm5",as.character("mmout"),as.integer(1),as.matrix(nrow=50,ncol=20,data=as.integer(rep(0,50))))
simon> This works alright until starts to read the 50 by 20 integer array.
simon> The bit about using as.matrix() to read the array do seem suspicious.
{indeed!}
simon> I do not know what is the proper way to read it.
Instead of your as.matrix(..) you could use matrix(),
also you should *assign* the result of .Fortran()
and you should use your space keybar to make things more
readable.
This leads to
r <- .Fortran("readmm5",
file = as.character("mmout"),
iflag = as.integer(1),
mif = matrix(as.integer(0), nrow=50,ncol=20))
where r is list where r[["mif"]] should be your desired matrix.
Alternatively, in your case,
mif <- .Fortran("readmm5",
file = as.character("mmout"),
iflag = as.integer(1),
mif = matrix(as.integer(0), nrow=50,ncol=20))[["mif"]]
Hoping this helps further,
Martin
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