Dear Paulo,
On May 25, 2005, at 8:01 PM, Paulo Brando wrote:
Dear All,
I have tried to calculate tree mean growth but I think the structure I
used below (growthresumo) is not the most elegant, even though it
worked. The only problem I had in this first part was that I cannot
use 'summary', just 'mean' (sorry but 'R' is pretty new for me).
In case you didn't notice, help(aggregate) indicates that 'FUN'
should be a scalar function, so summary won't work for that reason.
growthresumo <-
aggregate(growth[,c(16,19,23,27,31,35,39,43,47,52,56,60,64,68,72,76,81
,85,89,93,97,101,105,109,113,117,121,125,129,133,137,
141,145,149,153,157,161,165,169,173,177,181,185,189,194,197,201,205,209
,213,217,221,225,229,233,237,241)],
by=(growth[,c(3,8)]),MEAN,na.rm=TRUE)
It's hard to know where 'growth' came from. Is it your own data.frame,
or from a package? It's better to provide a reproducible or toy example
(as you'll often read here).
#after growth is calculated, I want to stack the results in just one
colunm.
growthvertical <- c(growthresumo[,3],...,growthresumo[,50]) # this is
very time consuming though
This comes to my mind:
as.vector(as.matrix(growthresumo[,3:50]))
but look up the help on stack() because it's a very powerful tool that
is aptly named (and might do everything you want).
Parcel <- c("C9","S8"..."C9","S8") # 50 items
rep() could help with the above.
date < c("DATE1"...."DATE50")
paste() will help with this.
growthpermonth <- data.frame(Parcel, Date, growthvertical)
Thank you very much!
Good luck with R!
Stephen
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