problem solved. thank you Jim and Spencer for your answers.
> This gives the same answer for what you have > supplied so far... > > > dat$d<-ifelse((dat$b-dat$a)>=1000,dat$b-dat$a+1,0) > > dat > a b c d > 1 1 1001 1001 1001 > 2 2 1001 0 0 > 3 3 1001 0 0 > 4 4 1001 0 0 > 5 1 1002 1002 1002 > 6 2 1002 1001 1001 > 7 3 1002 0 0 > 8 4 1002 0 0 > 9 1 1003 1003 1003 > 10 2 1003 1002 1002 > 11 3 1003 1001 1001 > 12 4 1003 0 0 > 13 1 1004 1004 1004 > 14 2 1004 1003 1003 > 15 3 1004 1002 1002 > 16 4 1004 1001 1001 > > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On > Behalf Of alex diaz > Sent: June 27, 2005 4:54 PM > To: [email protected] > Subject: [R] simplifying the code > > dear list: > > I made some corrections in the previous post > that had > some mistakes. > > I need help to achieve a simpler code to > complete a > task I'm performing. > here is an example: > > dat<-expand.grid(a=seq(1,4),b=seq(1001,1004)) > > #I want to add a new column dat$c in that: > > t1<-ifelse(dat$a==1&dat$b==1001,1001,0) > t2<-ifelse(dat$a==2&dat$b==1002,1001,0) > t3<-ifelse(dat$a==3&dat$b==1003,1001,0) > t4<-ifelse(dat$a==4&dat$b==1004,1001,0) > t5<-ifelse(dat$a==1&dat$b==1002,1002,0) > t6<-ifelse(dat$a==2&dat$b==1003,1002,0) > t7<-ifelse(dat$a==3&dat$b==1004,1002,0) > t8<-ifelse(dat$a==1&dat$b==1003,1003,0) > t9<-ifelse(dat$a==2&dat$b==1004,1003,0) > t10<-ifelse(dat$a==1&dat$b==1004,1004,0) > > dat$c<-t1+t2+t3+t4+t5+t6+t7+t8+t9+t10 > > My real data frame is much larger... I hope > someone > can help me with this. > > thanks for your help > > a. diaz ------------------------------------------------- Email Enviado utilizando o serviço MegaMail
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