Thanks for the prompt reply.
Your right, that was a weak example.
Consider this one though:
f <- function(n,x) (x-2.5)^2*n
g <- function(y) optimize(f,c(0,15), maximum=TRUE,x=y)$maximum*y
then if you try:
integrate(g,lower=0,upper=5)
it produces:
Error in optimize(f, c(0, 15), maximum = TRUE, x = y) :
invalid function value in 'optimize'
Any ideas?
My problem is a similar more complex function in which optimizaiton depends on
the value of the integrator.
"Huntsinger, Reid" <[EMAIL PROTECTED]> wrote:
In your example, f is a function, but
optimize(f,c(0,15),maximum=TRUE)$maximum is just a number (the point at
which f reaches its maximum value). I'm not sure what you want, but if you
had say
f <- function(x,y) x^3 + yx + 1
and defined
g <- function(y) optimize(f,c(0,5),maximum=TRUE,y)$maximum
then g(t) is the x-value at which the function f(x,t) (over x in (0,5))
reaches its maximum for this fixed t. That could then be integrated.
Reid Huntsinger
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Gregory Gentlemen
Sent: Thursday, July 28, 2005 3:58 PM
To: [email protected]
Subject: [R] using integrate with optimize nested in the integration
Hi guys
im having a problem getting R to numerically integrate for some function,
say f(bhat)*optimize(G(bhat)), over bhat. Where id like to integrate this
over some finite range, so that here as we integrate over bhat optimize
would return a different optimum.
For instance consider this simple example for which I cannot get R to return
the desired result:
f <- function(bhat) exp(bhat)
g <- function(bhat) optimize(f,c(0,15),maximum=TRUE)$maximum*bhat
integrate(g,lower=0,upper=5)
which returns:
187.499393759 with absolute error < 2.1e-12
However this is an approximation of : 15*(5^2/2 - 0)=187.5, not what I
intended on getting. Its not identifying that f is a function of bhat ...
any advice or ways I can get integrate to not treat this as a constant?
Any help is appreciated.
Gregoy Gentlemen
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