Thanks a lot! But unfortunately I will not know the dimensions of both lists.
And further, the lists may be (partly) disjoint as: x <- list("1"=c(a=1, b=2,
c=3), "2"=c(d=4, b=5, e=6)). And last but not least I'm really have to have
access to the names of the named list items.
The problem I dealt with is in unlist() merging the names together, as you can
see in your example given: "V1", "V2" and "V3". Because off interpreting the
names later as identifiers in db queries I'm really interested in getting
something like list("a"=c("1"=1), "b"=c("1"=2, "2"=5), "c"=c("1"=3),
"d"=c("1"=4), "e"=c("1"=6)) for the above input.
By giving the result this way I'm able to extract both names from two sets as
well as the according value between both items.
One point could be to build a matrix but this matrix would have many NA's. So I
prefer Lists of Lists.
Any ideas?
cheers
Jan
-----Ursprüngliche Nachricht-----
Von: Liaw, Andy [mailto:[EMAIL PROTECTED]
Gesendet: Montag, 15. August 2005 17:31
An: Jan Hummel; [email protected]
Betreff: RE: [R] Re-sort list of vectors
If all vectors in the list have the same length, why not use a matrix? Then
you'd just transpose the matrix if you need to. If you really have to have it
as a list, here's one possibility:
> x <- list("1"=c(a=1, b=2, c=3), "2"=c(a=4, b=5, c=6)) x
$"1"
a b c
1 2 3
$"2"
a b c
4 5 6
> as.list(as.data.frame(t(matrix(unlist(x), nrow=3))))
$V1
[1] 1 4
$V2
[1] 2 5
$V3
[1] 3 6
Andy
> From: Jan Hummel
>
> Hi.
> Can anyone suggest a simple way to re-sort in R a list of vectors of
> the following form?
>
> input
> $"1"
> a b c
> 1 2 3
> $"2"
> a b c
> 4 5 6
>
> Output should be something like:
> "a"
> "1" 1
> "2" 4
> "b"
> "1" 2
> "2" 5
> "c"
> "1" 3
> "2" 6
>
> I've been futzing with mapply(), outer(), split(), rbind() and so on
> but haven't found an elegant solution.
>
> Thanks,
> Jan.
>
> P.S. E-mailed CCs of posted replies appreciated.
>
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