Hi Lisa,
Try the following -- there are probably better solutions, but these seem
to work.
Hank Stevens
Miami University
Oxford, OH, USA
a <- vector("list",3)
names(a) <- 1:3
a[[1]] <- data.frame(x1=3,x2=1)
a[[2]] <- data.frame(x1=c(3,3),x2=c(2,2))
a[[3]] <- data.frame(x1=c(3,3), x2=c(3,3))
a
unlist(sapply(a, function(x) x$x1 ))
unlist(sapply(a, function(x) x[,1] ))
Lisa Wang wrote:
>Hello,
>
>I have a list "lis" as the following:
>
>$"1"
> x1 x2
>4 3 1
>
>$"2"
> x1 x2
>3 3 2
>5 3 2
>
>$"3"
> x1 x2
>2 3 3
>6 3 3
>
>How do I get the x1 varible? for example ss"1"
>
>
>
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