Here's one way: > unlist(lapply(x, function(x) x:(x+9))) [1] 1 2 3 4 5 6 7 8 9 10 15 16 17 18 19 20 21 22 23 24 [21] 30 31 32 33 34 35 36 37 38 39 45 46 47 48 49 50 51 52 53 54 [41] 60 61 62 63 64 65 66 67 68 69 90 91 92 93 94 95 96 97 98 99 [61] 115 116 117 118 119 120 121 122 123 124
Andy > From: Yves Magliulo > > hi, > > i have a vector like : > > x<-c(1,15,30,45,60,90,115) > > i know that step by step i have always more than 10 > > min(diff(x)) >=11 > > i want to add for each value a sequence of value:value+9 > result should be : > > 1 2 3 4 5 6 7 8 9 10 15 16 17 18 19 20 21 22 23 24 30 31 > (...) 39 45 46 > (...) 54 60 61 etc.. > > how can i do this without a loop (i'm sure there is a > "elegant" way like > always with R but i can't find it this time!) > > best, > > yves > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! > http://www.R-project.org/posting-guide.html > > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html