On Wed, 14 Dec 2005, January Weiner wrote:
Hi,
I read about the by() function, but it does not seem to do the job I
need. Here is the problem:
by() will work, you just need to use the right function in it.
You want
by(df[,-1], df$Day, function.that.means.each.column)
so all you need to do is write function.that.means.each.column()
In this case there is a built-in function, colMeans, so you don't even
have to write it.
More generally (eg the approach would work for medians as well)
by(df[,1], df$Day, function(today) apply(today, 2, mean))
Finally, you could just use aggregate().
-thomas
Say - I have a data frame, with three columns. The first one contains
strings that describe the data points, with repeats (for example, days
of a week). The other two contain numbers. Something like that:
Day val1 val2
Tue 1 2
Tue 2 8
Tue 3 5
Wed 1 2
Wed 1 8
etc.
Now I would like to have a data frame with averages for each week:
Day val1 val2
Tue 2 5
Wed 1 5
etc.
I now I can do tapply(DF$val2, DF$days, mean) to get the means for
val2. But I would like to have a data frame as result (as in reality I
have many more columns).
Further question: where can I find a good, advanced introduction to R
data types? R's help() function just kills my brain, and the tutorials
are very limited.
My kind regards,
January Weiner
--
------------ January Weiner 3 ---------------------+---------------
Division of Bioinformatics, University of Muenster | Schloßplatz 4
(+49)(251)8321634 | D48149 Münster
http://www.uni-muenster.de/Biologie.Botanik/ebb/ | Germany
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Thomas Lumley Assoc. Professor, Biostatistics
[EMAIL PROTECTED] University of Washington, Seattle
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