Here is another way:
> x <- scan('/tempxx.txt', what='', sep='\n', blank.lines.skip=F)
Read 7 items
> x
[1] "icsrvepf" "fpevrsci" "ics" "p" "" "f"
"ic"
> x <- strsplit(x, '') # break into single characters
> template <- c(i=0, c=0, s=0, r=0, v=0, e=0, p=0, f=0)
> mat <- lapply(x, function(.l){
+ .result <- template # initialize the result
+ .result[.l] <- 1
+ .result
+ })
> do.call('rbind', mat)
i c s r v e p f
[1,] 1 1 1 1 1 1 1 1
[2,] 1 1 1 1 1 1 1 1
[3,] 1 1 1 0 0 0 0 0
[4,] 0 0 0 0 0 0 1 0
[5,] 0 0 0 0 0 0 0 0
[6,] 0 0 0 0 0 0 0 1
[7,] 1 1 0 0 0 0 0 0
>
On 1/26/06, Thomas Lumley <[EMAIL PROTECTED]> wrote:
>
> On Thu, 26 Jan 2006, Dale Steele wrote:
> > The data looks like:
> > -->
> > icsrvepf
> > fpevrsci
> > ics
> > p
> >
> > f
> > ic
> > <--
> >
> > I would like to convert the about to a matrix of the form:
> >
> > i c s r v e p f
> > 1 1 1 1 1 1 1 1
> > 1 1 1 1 1 1 1 1
> > 1 1 1 0 0 0 0 0
> > 0 0 0 0 0 0 1 0
> > 0 0 0 0 0 0 0 0
> > 0 0 0 0 0 0 0 1
> > 1 1 0 0 0 0 0 0
> >
>
> One possibility is to use grep()
> > a
> [1] "icsrvepf" "fpevrsci" "p" "" "f" "ic"
> > grep("i",a)
> [1] 1 2 6
>
> so
> > results<-matrix(0,nrow=length(a),ncol=length(behaviours))
> > colnames(results)<-behaviours
> > for(b in behaviours) results[grep(b,a),b]<-1
> > results
> i c s r v e p f
> [1,] 1 1 1 1 1 1 1 1
> [2,] 1 1 1 1 1 1 1 1
> [3,] 0 0 0 0 0 0 1 0
> [4,] 0 0 0 0 0 0 0 0
> [5,] 0 0 0 0 0 0 0 1
> [6,] 1 1 0 0 0 0 0 0
> >
>
> -thomas
>
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--
Jim Holtman
Cincinnati, OH
+1 513 247 0281
What the problem you are trying to solve?
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