Hello, I am not very familiar with regular expressions and escaping. I
need to replace the %-signs in a character vector with elements as
"income 0%-33%# to be replaced by "income 0\%-33\%" (for later use in
LaTeX). Using
gsub("%","\\%","income 0%-33%")
does not give the desired result. However, gsub("%","\\\\%","income
0%-33%") gives "income 0\\%-33\\%", one backslash too much. What is the
appropriate expression to get the desired output (one backslash before
each %-sign)?
I am using R 2.1.0 on suse linux 9.2.
Thanks, Ruud
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