On 2/8/2006 9:21 AM, Bernhard Baumgartner wrote: > I have a dataframe with a column, say "x" consisting of values, each > value appearing different times, e.g. > x: 1,1,1,1,2,2,4,4,4,9,10,10,10,10,10 ... > and a vector, including e.g.: > y: 2,9,10,... > I need a subset of the dataframe: all rows where x is equal to one of > the values in y. Currently I use a loop for this, but because x and y > are large this is very slow. > Is there any idea how to solve this problem faster?
It's actually very easy. Assume your dataframe is df, then subset(df, x %in% y) will give you what you want (assuming there is no column y in the dataframe). Duncan Murdoch > Thank you, > Bernhard > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
