Just eyeballing your data it looks like a simple quadratic might be ok. plot(y ~ x) y.lm <- lm(y ~ poly(x, 2)) points(fitted(y.lm) ~ x, type = "b", col = 2)
On 2/16/06, Rangesh Kunnavakkam <[EMAIL PROTECTED]> wrote: > Dear Sir/Madam, > I have two vectors say x<-c(0,0,2.73,3.42,3.95,4.26) > and y<-c(0.0,0.5,1.20,1.90,2.6,3.3). I want to fit y as a function of x and > get the equation.Do I have to use glm() ? > Rangesh > > [[alternative HTML version deleted]] > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html > ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
