Hi,
"michael watson (IAH-C)" <[EMAIL PROTECTED]> writes:
> I have a list that has attributes:
>
> attributes(lis[2])
> $names
> [1] "150096_at"
>
> I want to use those attributes in a function and then use lapply to
> apply that function to every element of the list, eg for simplicity's
> sake:
>
> my.fun <- function(x) {
> attributes(x)
> }
This gets tricky. You said the right thing: you have a _list_ with
attributes. This does not mean the elements of the list have
attributes (unless they happen to).
> It seems that "attributes(x)" within the function is not the same as eg.
> "attributes(lis[2])" used outside of the function, ie the attributes
> have changed.
"[" on a list returns a sublist (with names copied over). The lapply
function is equivalent to accessing elements via "[[" which pulls out
a single element (no names).
For the specific case of processing a list with names, you may want:
for (name in names(x)) {
el <- x[[name]]
...
}
You could also try mapply.
+ seth
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