If c is c(c1, c2, c3) and x is c(x1, x2, x3) then
c+x is (c1+x1, c2+x2, c3+x3)
so sum(c+x) is c1+x1+c2+x2+c3+x3 = sum(c) + sum(x)
What you were expecting is given by:
rowSums(outer(1:4, c(-1,0,1), "+")) # gives c(3, 6, 9, 12)
Review the Introduction to R manual and also look at ?outer and ?rowSums
On 4/9/06, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> Hi, I am writing a function that includes 'sum' function
> such as:
> f<-function(x){
> c<-c(-1,0,1)
> f<-sum(c+x)
> }
> expecting f to be -1+x+0+x+1+x=3x. But I found out that f is
> sum(x). So, f is always a scalar, which means that f(c(0,1))
> is not a vector as c(0,3), but 3(0+1)=3. I would like to ask
> you helping me in solving this problem. I would like to
> thank you in advance.
> Sungsu.
> UC riverside.
>
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>
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