See ?truehist in the MASS package.
Philipp Pagel wrote: > On Thu, Apr 27, 2006 at 10:48:39AM -0700, [EMAIL PROTECTED] wrote: > >>Hi All, >> >>I want to use "hist" to get the relative frequency plot. But the range of >>ylab is greater than 1,which I think it should be less than 1 since it >>stands for the probability. >> >>I'm confused. Could you please help me with it? > > > I was pretty confused by that, too at first. The solution is that > freq=False cause hist to plot the DENSITY rather than frequency. And > density is not necesssarily the same as relative frequency. Excerpt from > ?hist: > > density: values f^(x[i]), as estimated density values. If > 'all(diff(breaks) == 1)', they are the relative frequencies > 'counts/n' and in general satisfy sum[i; f^(x[i]) > (b[i+1]-b[i])] = 1, where b[i] = 'breaks[i]'. > > If you want relative distance try something like this: > > myhist = hist(x,breaks=52, plot=F) > myhist$counts = myhist$counts / sum(myhist$counts) > plot(myhist,main=NULL,border=TRUE,xlab="days",xlim=c(0,6),lty=2) > > Not exactly clean, though -- we are messing with the myhist object... > > > cu > Philipp > ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
