gsub and sub support backreferences
sub("(.):(.)", "\\2:\\1", c("1:2", "5:6")) # c("2:1", "6:5")
# and you can capture them separately using strapply in the gsubfn package
# or perform function-based substitutions using gsubfn.
# Returns: list(c("1", "2"), c("5", "6"))
library(gsubfn)
strapply(c("1:2", "5:6"), "(.):(.)", function(z,x,y) c(x,y))
# same
strapply(c("1:2", "5:6"), "(.):(.)", c, backref = -2)
On 5/4/06, Sean Davis <[EMAIL PROTECTED]> wrote:
> Just a quick question....
>
> In perl, I can capture parts of a regex like /(\w)\/(\d)/ to get back $1 and
> $2 containing the parts of the regex in parentheses. Is there a parallel in
> R?
>
> Thanks,
> Sean
>
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