>>>>> "comtech" == comtech usa <[EMAIL PROTECTED]>
>>>>> on Tue, 23 May 2006 23:14:21 -0700 writes:
comtech> imagine when you have complicated matrix algebra computation using
R,
comtech> you cannot prevent some middle-terms become quadratic and absorbs
into one
comtech> scalar, right?
comtech> if R cannot intelligently determine this, and you have to
manually add
comtech> "drop" everywhere,
comtech> do you think it is reasonable?
I don't think you can find any reasonable example where
`` you have to manually add "drop" everywhere ''.
To the contrary: In my experience, the S behavior (which won't
be changed -- forget about that if you still consider it!!),
is even rather useful, pointing to ``infelicities'' in your code
most of the time, when matrix dimensions do not match.
Further note, that c( <1x1--matrix> ) also produces a scalar
and gives slightly more readable formulae --- however in the
present case, c() is only advisable if you *know* you don't have
a ``proper'' (n x k, with n, k > 1) matrix.
Martin Maechler, ETH Zurich
comtech> On 5/23/06, Patrick Burns <[EMAIL PROTECTED]> wrote:
>>
>> I think
>>
>> drop(B/D) * solve(A)
>>
>> would be a more transparent approach.
>>
>> It isn't that R can not do what you want, it is that
>> it is saving you from shooting yourself in the foot
>> in your attempt. What you are doing is not really
>> a matrix computation.
>>
>>
>> Patrick Burns
>> [EMAIL PROTECTED]
>> +44 (0)20 8525 0696
>> http://www.burns-stat.com
>> (home of S Poetry and "A Guide for the Unwilling S User")
>>
>> Michael wrote:
>>
>> >This is very strange:
>> >
>> >I want compute the following in R:
>> >
>> >g = B/D * solve(A)
>> >
>> >where B and D are quadratics so they are just a scalar number, e.g.
>> B=t(a)
>> >%*% F %*% a;
>> >
>> >I want to multiply B/D to A^(-1),
>> >
>> >but R just does not allow me to do that and it keeps complaining that
>> >"nonconformable array, etc."
>> >
>> >
>> >I tried the following two tricks and they worked:
>> >
>> >as.numeric(B/D) * solve(A)
>> >
>> >diag(as.numeric(B/D), 5, 5) %*% solve (A)
>> >
>> >----------------------------
>> >
>> >But if R cannot intelligently do scalar and matrix multiplication, it is
>> >really problemetic.
>> >
>> >It basically cannot be used to do computations, since in complicated
>> matrix
>> >algebras, you have to distinguish where is scalar, and scalars obtained
>> from
>> >quadratics cannot be directly used to multiply another matrix, etc. It
is
>> >going to a huge mess...
>> >
>> >Any thoughts?
>> >
>> > [[alternative HTML version deleted]]
>> >
>> >______________________________________________
>> >R-help@stat.math.ethz.ch mailing list
>> >https://stat.ethz.ch/mailman/listinfo/r-help
>> >PLEASE do read the posting guide!
>> http://www.R-project.org/posting-guide.html
>> >
>> >
>> >
>> >
>>
comtech> [[alternative HTML version deleted]]
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