Duncan Murdoch <[EMAIL PROTECTED]> writes: > Suppose I have two columns, x,y. I can use order(x,y) to calculate a > permutation that puts them into increasing order of x, > with ties broken by y. > > I'd like instead to calculate the rank of each pair under the same > ordering, but the rank() function doesn't take multiple values > as input. Is there a simple way to get what I want? > > E.g. > > > x <- c(1,2,3,4,1,2,3,4) > > y <- c(1,2,3,1,2,3,1,2) > > rank(x+y/10) > [1] 1 3 6 7 2 4 5 8 > > gives me the answer I want, but only because I know the range of y and > the size of gaps in the x values. What do I do in general?
Still not quite general, but in the absence of ties: > z[order(x,y)]<-1:8 > z [1] 1 3 6 7 2 4 5 8 -- O__ ---- Peter Dalgaard Øster Farimagsgade 5, Entr.B c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - ([EMAIL PROTECTED]) FAX: (+45) 35327907 ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
