On Mon, 2006-06-26 at 12:40 -0500, [EMAIL PROTECTED] wrote: > Hi : I think I need to use sapply but I can't figure this out. > > Suppose I have two vectors : tempa ( 4, 6,10 ) and tempb > ( 11,23 ,39 ) > > > I want a function that returns 4:11,6:23 and 10:39 as vectors. > > I tried : > > sapply(1:length(tempa) function (z) seq(tempa[z],tempb[z]) > > but i got 3 really strange vectors back in the sense that the numbers > in them did not make no sense to me. obviously, > i must be doing something wrong. thanks a lot. > > mark
Mark, Try this using mapply(): tempa <- c(4, 6, 10) tempb <- c(11, 23, 39) > mapply(seq, from = tempa, to = tempb) [[1]] [1] 4 5 6 7 8 9 10 11 [[2]] [1] 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 [[3]] [1] 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 [23] 32 33 34 35 36 37 38 39 You will get a list back in this case and you can then deal with the 3 vectors as you require. Each vector is a different length, so a list is about the only way to return them here. See ?mapply for more info. HTH, Marc Schwartz ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
