Hi,
I would really appreciate any suggestions on this (rather trivial) problem..
Say I have two vectors:
v1=seq(1:10)
v2=seq(1:15)
For a set of common breaks I need to divide the density of v2 over v1. This
means that I want to avoid having 0 counts for any v1 breakpoint. But
(unsuprisingly) if I define my common breaks as those returned by calling hist
for v1:
v1.hist=hist(v1, plot=F)
v2.hist=hist(v2, plot=F, breaks=v1.hist$breaks)
I get an error:
Error in hist.default(v1, plot = F, breaks = v2.hist$breaks) :
some 'x' not counted; maybe 'breaks' do not span range of 'x'
If I had used the combined vector (c(v1,v2)) to set my breaks I would end up
with 0 for some v1 counts. So my question is: is there a way to define breaks
that cover the whole range of v1 and v2 while avoiding having 0 for the
shortest vector?
Many thanks
Eleni Rapsomaniki
Birkbeck College, UK
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