s<-data.frame(var.name=seq(1,6,by=2))
s
var.name
1 1
2 3
3 5
2006/7/7, zhijie zhang <[EMAIL PROTECTED]>:
Dear friends,
The "s" in the following argument don't have a variable name, how should i
give it a name?
> s<-data.frame(seq(1,6,by=2))
> s
seq.1..6..by...2.
1 1
2 3
3 5
thanks very much!
--
Kind Regards,
Zhi Jie,Zhang ,PHD
Department of Epidemiology
School of Public Health
Fudan University
Tel:86-21-54237149
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--
黄荣贵
Department of Sociology
Fudan University
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