The format is like this.
Plot species Value
P1 ACERRUB 3
P2 MAGNVIR 2
P3 ARONARB 2
etc.
imported using x<-read.table(file="filename.txt")
I want to replace a list of values in the 2nd column with another list. For
example, I want to replace ARONARB with PHOTPYR.
list<-read.table(file="originalnames.txt")
replace<-read.table(file="replacementnames.txt")
I tried to use replace in this manner:
newx<-replace(x,list,replace)
however, I get the error message: error in replace, invalid subscript type.
I have tried transforming the above list and modifying the column names
(column 2), but to no avail. I hope this clarifies a little. Sorry about
that.
On 7/7/06, Marc Schwartz (via MN) <[EMAIL PROTECTED]> wrote:
>
> On Fri, 2006-07-07 at 11:20 -0400, Wade Wall wrote:
> > Hi all,
> >
> > I have a three columned list that I have imported into R. The first
> column
> > is a plot (ex. Plot1), the second is a species name (ex ACERRUB) and the
> > third a numeric value. I want to replace some of the second column
> names
> > with other names (for example replace ACERRUB with ACERDRU). The
> original
> > and replacement values are in separate lists (not vectors), but I can't
> seem
> > to find the right function to perform this. The replace function seems
> to
> > only want to work with numbers.
> >
> > Any clues?
> >
> > Wade
>
> Without seeing the code you are using, we can only guess a syntax error
> of some sort. It works fine using the iris dataset:
>
> > head(iris)
> Sepal.Length Sepal.Width Petal.Length Petal.Width Species
> 1 5.1 3.5 1.4 0.2 setosa
> 2 4.9 3.0 1.4 0.2 setosa
> 3 4.7 3.2 1.3 0.2 setosa
> 4 4.6 3.1 1.5 0.2 setosa
> 5 5.0 3.6 1.4 0.2 setosa
> 6 5.4 3.9 1.7 0.4 setosa
> 7 4.6 3.4 1.4 0.3 setosa
> 8 5.0 3.4 1.5 0.2 setosa
> 9 4.4 2.9 1.4 0.2 setosa
> 10 4.9 3.1 1.5 0.1 setosa
>
> > iris$Species <- replace(iris$Species, iris$Species == "setosa",
> "NewValue")
>
> > head(iris)
> Sepal.Length Sepal.Width Petal.Length Petal.Width Species
> 1 5.1 3.5 1.4 0.2 NewValue
> 2 4.9 3.0 1.4 0.2 NewValue
> 3 4.7 3.2 1.3 0.2 NewValue
> 4 4.6 3.1 1.5 0.2 NewValue
> 5 5.0 3.6 1.4 0.2 NewValue
> 6 5.4 3.9 1.7 0.4 NewValue
> 7 4.6 3.4 1.4 0.3 NewValue
> 8 5.0 3.4 1.5 0.2 NewValue
> 9 4.4 2.9 1.4 0.2 NewValue
> 10 4.9 3.1 1.5 0.1 NewValue
>
>
> HTH,
>
> Marc Schwartz
>
>
>
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