Try this:

library(zoo)
as.Date(11328)

See the Help Desk article in R News 4/1 for more on dates.


On 7/11/06, pierre clauss <[EMAIL PROTECTED]> wrote:
> Hi everybody,
> I need your precious help for, I think, a simple request, but I do not manage 
> to solve this.
>
> When I use a "table" function with dates in the rows, the rows are coerced to 
> number after the table function.
>
> So I need to transform the row names into date format. But I do not manage.
>
> Therefore, for an example, I manage to write this :
>
> datetest<-"06/01/2001"
> datetest<-as.Date(datetest,"%d/%m/%Y")
> datetest<-as.numeric(datetest)
>
> to get 11328.
>
> But I do not obtain the inverse tranformation :
>
> datetest<-as.Date(datetest,"%d/%m/%Y")
>
> How do we get this please ?
>
> Thanks a lot for your solution.
> Pierre.
>
>
>
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