See

?aov
?lm

something like
 
lm(result~yourfactor1+yourfactor2+yourfactor3+yourfactor5, 
data=yourdataframe)
or
aov(result~yourfactor1+yourfactor2+yourfactor3+yourfactor5, 
data=yourdataframe)

but the exact structure of lm or aov construction depends on what you 
want to test.

HTH
Petr


On 28 Jul 2006 at 21:43, [EMAIL PROTECTED] wrote:

Date sent:              Fri, 28 Jul 2006 21:43:38 -0700
From:                   [EMAIL PROTECTED]
To:                     r-help@stat.math.ethz.ch
Subject:                [R] DOE in R
Send reply to:          [EMAIL PROTECTED]
        <mailto:[EMAIL PROTECTED]>
        <mailto:[EMAIL PROTECTED]>

> Hi.
> 
> I'm a student in a graduate program at Simon Fraser University in
> Canada.
> 
> I am trying to run a simple screening experiment with some simulated
> data.
> 
> I simply want to do an ANOVA of an experiemnt with 5 factors (4 have 2
> levels, the last has 3 levels) and 48 runs (ie, full factorial).
> 
> The thing is that I have multiple observations for each level
> combination (run).
> 
> So,
> 
> 1) How do I do the anova based on the setup above?
> 
> and 
> 
> 2) More importantly, because of convergence issues for my simulations,
> I will likely have an unequal number of observations for the 48 runs.
> How can I do this?
> 
> Seems like a straightforward enough situation.
> 
> I am trying to avaoid writing my own C code to do the analysis since I
> am working under some pretty tight time constraints.
> 
> ANy help would be appreciated.
> 
> Thanks very much.
> 
> Dean Vrecko
> 
> ______________________________________________
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html and provide commented,
> minimal, self-contained, reproducible code.

Petr Pikal
[EMAIL PROTECTED]

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