Assuming this data:
s <- structure(list(L.qol.0 = 83, L.qol.0.08 = 86, L.qol.0.17 = 89,
L.qol.0.25 = 92, L.qol.0.5 = 91, L.qol.0.42 = 87, L.qol.0.34 = 90),
.Names = c("L.qol.0", "L.qol.0.08", "L.qol.0.17", "L.qol.0.25",
"L.qol.0.5", "L.qol.0.42", "L.qol.0.34"),
class = "data.frame", row.names = "1")
# we can sort it by column names like this:
s[,sort(names(s))]
# also note that mixed sort in gtools can sort by numeric
# value in mixed character/numeric names which gives the
# same result here but may not in different examples
library(gtools)
s[,mixedsort(names(s))]
On 8/2/06, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I am working on some longitudinal data in wide format and I am having a
> problem ordering the data columns. To expand, a subset of what I am working
> on is as follows;
>
> >s
> L.qol.0 L.qol.0.08 L.qol.0.17 L.qol.0.25 L.qol.0.5 L.qol.0.42 L.qol.0.34
> 1 83 86 89 92 91 87 90
>
> >names(s)
> [1] "L.qol.0" "L.qol.0.08" "L.qol.0.17" "L.qol.0.25" "L.qol.0.5"
> [6] "L.qol.0.42" "L.qol.0.34"
>
> # in this object s (not a vector), 'L.qol' is measured at time points 0,
> 0.08, 0.17, 0.25, 0.34, 0.42 and 0.5. As you can see, however, the time
> points are not in the correct order in object s. Does anyone know how to
> order these column names along with their corresponding measurements?
> Clearly s[order(s)] does not work since this just orders the corresponding
> measurements.
>
> I would be extremely grateful for any help on this matter, it may be really
> simple, but I have tried for ages.
>
> Thank you,
>
> Zoe
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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