Antonio Olinto wrote: > Hi, > > I'd like to find which values of x will give me a y. > > In other words, in the example of a gaussian curve, I want to find the values > of > x that will give me a density, let's say, of 0.02. > > curve(((1/(sqrt(2*pi)*10))*exp(-((x-50)^2)/(2*10^2))),xlim=c(0,100))
Numerical optimization might help: optimize( function(x) (1/(sqrt(2*pi)*10) * exp(-((x-50)^2)/(2*10^2)) - 0.02)^2, interval = c(0, 50)) Uwe Ligges > Thanks for any help, > > Antonio Olinto > > > > > ------------------------------------------------- > WebMail Bignet - O seu provedor do litoral > www.bignet.com.br > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
