On Wed, 2006-08-16 at 10:42 +0300, Atte Tenkanen wrote:
> Is there some (much) more efficient way to do this?
>
> VECTOR=c(3,2,4,5,5,3,3,5,1,6,6);
> NEWVECTOR=VECTOR[1];
>
> for(i in 1:(length(VECTOR)-1))
> {
> if((identical(VECTOR[i], VECTOR[i+1]))==FALSE){
> NEWVECTOR=c(NEWVECTOR,VECTOR[i+1])}
> }
>
> > VECTOR
> [1] 3 2 4 5 5 3 3 5 1 6 6
> > NEWVECTOR
> [1] 3 2 4 5 3 5 1 6
>
> _______________________________
> Atte Tenkanen
Is this what you mean?
x <- c(3, 2, 4, 5, 5, 3, 3, 5, 1, 6, 6)
x.wanted <- c(3, 2, 4, 5, 3, 5, 1, 6)
X <- x[diff(x) != 0]
all.equal(x.wanted, X) # check it works
G
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