Here are two solutions. In both we break up DF into rows which start with 1.
In solution #1 we create a new data frame with the required sequence for A and zeros for B and then we fill it in. In solution #2 we convert each set of rows to a zoo object z where column A is the times and B is the data. We convert that zoo object to a ts object (which has the effect of filling in the missing times) and then create a zoo object with no data from its times merging that zoo object with z using a fill of 0. Finally in both solutions we reconstruct the rows from that by rbind'ing everything together. # 1 f <- function(x) { DF <- data.frame(A = 1:max(x$A), B = 0) DF[x$A,"B"] <- x$B DF } do.call(rbind, by(DF, cumsum(DF$A == 1), f)) # 2 library(zoo) f <- function(x) { z <- zoo(x$B, x$A) ser <- merge(zoo(,time(as.ts(z)), z, fill = 0) data.frame(A = time(ser), B = coredata(ser)) } do.call(rbind, by(DF, cumsum(DF$A == 1), f) On 8/18/06, Sachin J <[EMAIL PROTECTED]> wrote: > Hi, > > I have following dataframe. Column A indicates months. > > DF <- structure(list(A = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, > 2, 3, 4, 5, 7, 8, 11, 12, 1, 2, 3, 4, 5, 8), B = c(0, 0, 0, 8, > 0, 19, 5, 19, 0, 0, 0, 11, 0, 8, 5, 11, 19, 8, 11, 10, 0, 8, > 36, 10, 16, 10, 22)), .Names = c("A", "B"), class = "data.frame", row.names = > c("1", > "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", > "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", > "25", "26", "27")) > > There is some discontinuity in the data. For example month 6, 9,10 data (2nd > year) and month 6 data (3rd year) are absent. I want to insert the rows in > place of these missing months and set the corresponding B column to zero. > i.e., the result should look like: > > DFNEW <- structure(list(A = c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, > 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 1, 2, 3, 4, 5, 6, 7, 8), > B = c(0, 0, 0, 8, 0, 19, 5, 19, 0, 0, 0, 11, 0, 8, 5, 11, > 19, 0, 8, 11, 0, 0, 10, 0, 8, 36, 10, 16, 10, 0, 0, 22)), .Names = c("A", > "B"), class = "data.frame", row.names = c("1", "2", "3", "4", > "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", > "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", > "27", "28", "29", "30", "31", "32")) > > Thanks in advance. > > Sachin > > > --------------------------------- > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.