Is there a simple function or process that will create permutations with
replacement?
I know that using the combinat package
###### begin R code ######
> library(combinat)
> m <- t(array(unlist(permn(3)), dim = c(3, 6)))
# we can get the permutations, for example 3!=6
# gives us
> m
[,1] [,2] [,3]
[1,] 1 2 3
[2,] 1 3 2
[3,] 3 1 2
[4,] 3 2 1
[5,] 2 3 1
[6,] 2 1 3
###### end R code ##########
I'd like to include the "with replacement possibilities" such as
1,1,3
1,1,2
2,3,3
and so on. This will eventually be done on 8!=40,320 rather than the
development version using 3! as above.
If no function exists (I've Googled on CRAN with no palpable luck), then
perhaps this is more of a bootstrap type problem.
Thanks for your help in advance,
Jesse Canchola
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