I suspect you are not thinking about the list and the
subsetting/extraction operators in the right way.
A list contains a number of components.
To get a subset of the list, use the '[' operator. The subset can
contain zero or more components of the list, and it is a list itself.
So, if x is a list, then x[2] is a list containing a single component.
To extract a component from the list, use the '[[' operator. You can
only extract one component at a time. If you supply a vector index with
more than one element, it will index recursively.
> x <- list(1,2:3,letters[1:3])
> x
[[1]]
[1] 1
[[2]]
[1] 2 3
[[3]]
[1] "a" "b" "c"
> # a subset of the list
> x[2:3]
[[1]]
[1] 2 3
[[2]]
[1] "a" "b" "c"
> # a list with one component:
> x[2]
[[1]]
[1] 2 3
> # the second component itself
> x[[2]]
[1] 2 3
> # recursive indexing
> x[[c(2,1)]]
[1] 2
> x[[c(3,2)]]
[1] "b"
>
Rainer M Krug wrote:
> Hi
>
> I use the following code and it stores the results of density() in the
> list dr:
>
> dens <- function(run) { density( positions$X[positions$run==run], bw=3,
> cut=-2 ) }
> dr <- lapply(1:5, dens)
>
> but the results are stored in dr[[i]] and not dr[i], i.e. plot(dr[[1]])
> works, but plot([1]) doesn't.
>
> Is there any way that I can store them in dr[i]?
>
> Thanks a lot,
>
> Rainer
>
>
>
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