Hi
On 8 Sep 2006 at 10:33, Graham Smith wrote:
Date sent: Fri, 8 Sep 2006 10:33:49 +0100
From: "Graham Smith" <[EMAIL PROTECTED]>
To: "Petr Pikal" <[EMAIL PROTECTED]>
Copies to: r-help@stat.math.ethz.ch
Subject: Re: [R] subsetting a data set
> Petr,
>
> Thanks again, but the data is GQ1, Max is a variable (column)
>
> So I have used
>
> by(GQ1[,"Max"], list(GQ1$Status), summary)
>
> Which is very good, and is better than the way I did it before by
> summarising for each status level individually, but that still isn't
> combing the data for Status == "Expert" and Status = "Ecol"
>
> So at the moment the status variable has 3 levels Expert, Ecol and
> Stake,
look at ?factors how to deal with factors, if your variable is not a
factor (see ?str) than turn it to one.
x<-sample(letters[1:3], 20, replace=T) #character
x.f<-as.factor(x) #turn to factor
> x.f
[1] b c b a c a c a a a a a b c c c b b c b
Levels: a b c
> levels(x.f)<-c("x","x","y") #rename levels
> x.f
[1] x y x x y x y x x x x x x y y y x x y x
Levels: x y
>
>
> I want to analsye that at two levels: Expert and Ecol combined into a
> new level called "AllEcol" and the exsiting level "Stake"
so in your case something like
GQ1$statusComb<-factor(GQ1$status, labels=c("AllEcol","AllEcol",
"Stake"))
shall do it. Beware of label ordering!!!
BTW. It had been good if you provided a usable example, as stated in
posting guide. Many times trying to elaborate an example I will solve
the problem myself.
HTH
Petr
>
> It is this combining the levels that has got me stuck.
>
> Thanks again,
>
> Graham
>
> On 08/09/06, Petr Pikal <[EMAIL PROTECTED]> wrote:
> >
> > Sorry, I did not notice that in your case Max is not a function but
> > your data. So probably
> >
> > by(Max[, your.columns], list(Max$status), summary)
> >
> > is maybe what you want.
> > HTH
> > Petr
> >
> >
> > On 8 Sep 2006 at 10:31, Petr Pikal wrote:
> >
> > From: "Petr Pikal" <[EMAIL PROTECTED]>
> > To: "Graham Smith" <[EMAIL PROTECTED]>,
> > r-help@stat.math.ethz.ch
> > Date sent: Fri, 08 Sep 2006 10:31:12 +0200
> > Priority: normal
> > Subject: Re: [R] subsetting a data set
> >
> > > Hi
> > >
> > > I am not sure if your Max is the same as max so I am not sure what
> > > you exactly want from your data. However you shall consult
> > > ?tapply, ?by, ?aggregate and maybe also ?"[" together with chapter
> > > 2 in intro manual in docs directory.
> > >
> > > aggregate(data[, some.columns], list(data$factor1, data$factor2),
> > > max)
> > >
> > > will give you maximum for specified columns based on spliting the
> > > data according to both factors
> > >
> > > Also connection summary with max is not common and I wonder what
> > > is your output in this case. I believe that there are six same
> > > numbers. However R is case sensitive and maybe Max does something
> > > different from max. In my case it throws an error.
> > >
> > > HTH
> > > Petr
> > >
> > > On 8 Sep 2006 at 8:06, Graham Smith wrote:
> > >
> > > Date sent: Fri, 8 Sep 2006 08:06:16 +0100
> > > From: "Graham Smith" <[EMAIL PROTECTED]>
> > > To: r-help@stat.math.ethz.ch
> > > Subject: [R] subsetting a data set
> > >
> > > > I have a data set called GQ1, which has 20 variables one of
> > > > which is a factor called Status at thre levels "Expert", "Ecol"
> > > > and "Stake"
> > > >
> > > > I have managed to evaluate some of the data split by status
> > > > using commands like:
> > > >
> > > > summary (Max[Status=="Ecol"])
> > > >
> > > > BUT how do I produce asummary for Ecol and Expert combined, the
> > > > only example I can find suggsts I could use
> > > >
> > > > summary (Max[Status=="Ecol"& Status=="Expert"]) but that doesn't
> > > > work.
> > > >
> > > > Additionally on the same vein, if I cannot work out how to
> > > > create a new data set that would contain all the data for all
> > > > the variables but only for the data where Status = Ecol, or
> > > > where status equalles Ecol and Expert.
> > > >
> > > > I know this is yet again a very simple problem, but I really
> > > > can't find the solution in the help or the books I have.
> > > >
> > > > Many thanks,
> > > >
> > > > Graham
> > > >
> > > > [[alternative HTML version deleted]]
> > > >
> > > > ______________________________________________
> > > > R-help@stat.math.ethz.ch mailing list
> > > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > > PLEASE do read the posting guide
> > > > http://www.R-project.org/posting-guide.html and provide
> > > > commented, minimal, self-contained, reproducible code.
> > >
> > > Petr Pikal
> > > [EMAIL PROTECTED]
> > >
> > > ______________________________________________
> > > R-help@stat.math.ethz.ch mailing list
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
> > > http://www.R-project.org/posting-guide.html and provide commented,
> > > minimal, self-contained, reproducible code.
> >
> > Petr Pikal
> > [EMAIL PROTECTED]
> >
> >
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html and provide commented,
> minimal, self-contained, reproducible code.
Petr Pikal
[EMAIL PROTECTED]
______________________________________________
R-help@stat.math.ethz.ch mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
