Note that xpnd(v), which you mentioned in your post, is a linear transform whose effect on v is the same as D_n %*% v so just pump an identity matrix through xpnd to get its matrix:
library(MCMCpack) D_n <- function(n) apply(diag(n*(n+1)/2), 2, xpnd, n) # test D_n(3) On 9/9/06, w <[EMAIL PROTECTED]> wrote:
Dear R-list members, Just wondering if there is any way to compute the duplication matrix in R. I tried to search for it but only found functions "xpnd" and "vech". Basically for a symmetric n by n matrix A, the duplication matrix D_n is a matrix of dimension n^2 by n(n+1)/2 such that D_n vech(A)= c(A), where c(A) just vectorizes A. The duplication matrix is defined on page 49 of the book "Matrix differential calculus with applications in statistics and econometrics" by Magnus and Neudecker (1988 ) Thanks a lot! --------------------------------- 雅虎免费邮箱-3.5G容量,20M附件 [[alternative HTML version deleted]] ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.