Fellow R-helpers, Suppose we create a histogram as follows (although it could be any vector with zeroes in it):
R> lenh <- hist(iris$Sepal.Length, br=seq(4, 8, 0.05)) R> lenh$counts [1] 0 0 0 0 0 1 0 3 0 1 0 4 0 2 0 5 0 6 0 10 0 9 0 4 0 [26] 1 0 6 0 7 0 6 0 8 0 7 0 3 0 6 0 6 0 4 0 9 0 7 0 5 [51] 0 2 0 8 0 3 0 4 0 1 0 1 0 3 0 1 0 1 0 0 0 1 0 4 0 [76] 0 0 1 0 0 and we wanted to apply a weighing scheme where frequencies immediately following (and only those) empty class intervals (0) should be adjusted by averaging them over the number of preceding empty intervals + 1. For example, the first frequency that would need to be adjusted in 'lenh' is element 6 (1), which has 5 preceding empty intervals, so its adjusted count would be 1/6. Similarly, the second one would be element 8 (3), which has 1 preceding empty interval, so its adjusted count would be 3/2. Can somebody please provide a hint to implement such a weighing scheme? I thought about some very contrived ways to accomplish this, involving 'which' and 'diff', but I sense a function might already be available to do this efficiently. I couldn't find relevant info in the usual channels. Thanks in advance for any pointers. Cheers, -- Seb ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
