Dear R users, Sorry, I made a mistake in my specification of problem, should be:
# my vector is this a.vector <- seq(2, by=5, length=1000) # so my cut values are cut.values <- c(30, 50, 100, 109, 300, 601, 803, 1000) # and x should have an extra ")" at the end x <- rep(1:length(cut.values), times=diff(c(0, cut.values))) Thanks for all the responses so far. Any additional responses are welcome. Many thanks, Dave --- Dave Evens <[EMAIL PROTECTED]> wrote: > > Dear R users, > > I have a huge vector that I would like to split into > unequal slices. However, the only way I can do this > is > to create another huge vector to define the groups > that are used to split the original vector, e.g. > > # my vector is this > a.vector <- seq(2, by=5, length=100) > > # indices where I would like to slice my vector > cut.values <- c(30, 50, 100, 109, 300, 601, 803) > > # so I have to create another vector of similar > length > # to use the split() command, i.e. > x <- rep(1:length(cut.values), times=diff(c(0, > cut.values)) > > # this means I can use split() > split(a.vector, x) > > This seems to be a waste in terms of memory usage as > I'm creating another vector (here "x") to split the > original vector. Is there a better way to split a > huge > vector than this? Any help is much appreciated. > > Best, > Dave. > > > __________________________________________________ > Do You Yahoo!? > protection around > http://mail.yahoo.com > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.