Here's one way:
R> x <- c(6,11,5,14,30,11,17,3,9,3,8,8)
R> confint(lm(x~1), level=.9)
5 % 95 %
(Intercept) 6.546834 14.2865
Andy
From: Ethan Johnsons
>
> I have a quick question, please.
>
> Does R have function to compute i.e. a 90% confidence
> interval for the mean for these numbers?
>
> > mean (6,11,5,14,30,11,17,3,9,3,8,8)
> [1] 6
>
> I thought pt or qt would give me the interval, but it seems not.
>
> thx much.
>
> ej
>
> ______________________________________________
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
>
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