try this: start.val <- 2 end.val <- 6500 system.time(res <- unlist(lapply(start.val:end.val, ":", to = end.val)))
I hope it helps. Best, Dimitris ---- Dimitris Rizopoulos Ph.D. Student Biostatistical Centre School of Public Health Catholic University of Leuven Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +32/(0)16/336899 Fax: +32/(0)16/337015 Web: http://med.kuleuven.be/biostat/ http://www.student.kuleuven.be/~m0390867/dimitris.htm Quoting Julian Burgos <[EMAIL PROTECTED]>: > Hello fellow R's, > > I'm sure there must be an easy way to do this. But after digging in the > documentation and thinking about it for a while I couldn't figure it > out. I need to get a decreasing recursive vector in. I mean something > like this: if starting at 2, and ending at 6, the vector should be > > 2 3 4 5 6 3 4 5 6 4 5 6 5 6 6 > > An easy way would be to do this > > x <- integer(0) > for (i in 5) x <- c(x, i:5) > > But I need to create really long vectors (where the ending value is in > the order of 6500) , and using loops is way to slow. I'm looking for a > vectorized method. Any help will be welcomed. > > Julian > > Julian M. Burgos > > Fisheries Acoustics Research Lab > School of Aquatic and Fishery Science > University of Washington > > 1122 NE Boat Street > Seattle, WA 98105 > > Phone: 206-221-6864 > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
