A quick question, please.
46 e coli lab samples are tested, 6 of them returned positive.
So, the best point estimate for p is 6/46 = 0.1304348.
For a 95% CI for p, I thought binom.test would give me the correct
result, but it seems it is not the right function to use. What is
the R function for this?
> binom.test(x=6, n=46, p=4/16, conf.level = 0.95)
Exact binomial test
data: 6 and 46
number of successes = 6, number of trials = 46, p-value = 0.0621
alternative hypothesis: true probability of success is not equal to 0.25
95 percent confidence interval:
0.04940735 0.26256502
sample estimates:
probability of success
0.1304348
thx much,
ej
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