try this:
dat <- data.frame(x = rnorm(100), y = sample(rep(1:2, each = 50)), z =
sample(rep(1:4, 25)))
#########
nams <- c("y", "z")
dat[do.call(order, dat[nams]), ]
I hope it helps.
Best,
Dimitris
----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
----- Original Message -----
From: "michael watson (IAH-C)" <[EMAIL PROTECTED]>
To: <r-help@stat.math.ethz.ch>
Sent: Tuesday, November 28, 2006 11:45 AM
Subject: [R] Sorting a data frame when you don't know the columns
> Hi
>
> Sorry to ask such a well oiled question, but even with multiple
> google hits I don't think this has been answered very well.
>
> It's all well and good doing a sort of a data frame on multiple
> columns when you know in advance which columns you want to sort on,
> but what about when the names of the columns you wish to sort on are
> in a vector?
>
> At the minute I'm messing about with paste() to form a string that
> works for order() and then calling do.call(). Is this really the
> best way of doing it?
>
> Thanks
> Mick
>
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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