rm(list=ls(all=TRUE))
        graphics.off()
        # make a test matrix:
        nr<- 3
        nc<- 4
        # the data:
        ( m<- matrix((1:(nr*nc)), nr, nc) )
             [,1] [,2] [,3] [,4]
        [1,]    1    4    7   10
        [2,]    2    5    8   11
        [3,]    3    6    9   12

        # the way that levelplot (and image) displays the data:
        t(m)[dim(t(m))[1]:1, ]
             [,1] [,2] [,3]
        [1,]   10   11   12
        [2,]    7    8    9
        [3,]    4    5    6
        [4,]    1    2    3

        # undo what levelplot does by performing the inverse transformation
        inverse<- function(x) t(x[dim(x)[1]:1, ]) 

        windows(); levelplot(m, main="levelplot(m)")
        windows(); levelplot(inverse(m), main="levelplot(inverse(m))")

        > Message: 7
        > Date: Mon, 11 Dec 2006 12:28:17 +0000 (GMT)
        > From: Jenny Barnes <[EMAIL PROTECTED]>
        > Subject: [R] upside down image/data
        > To: [email protected]
        > Message-ID: <[EMAIL PROTECTED]>
        > Content-Type: TEXT/plain; charset=us-ascii
        > 
        > Dear R-community,
        > 
        > I am looking for some simple advice - I have a matrix (therefore 2 
dimensional) 
        > of global temperature. 
        > 
        > Having read R-help I think that when I ask R to image() or 
levelplot() my matrix 
        > will it actually appear upside down - I think I therefore need to use 
the line:
        > > levelplot(temperature.matrix[,ncol(output.temp):1], ........)
        > to get it looking like it was on the globe due to the matrix rows 
increasing in 
        > number down the matrix in its dimensions on longitude and latitude 
but the 
        > y-axis coordinates increase up the axis.
        > 
        > Can anyone simply tell me whether this is correct as I find it very 
hard to know 
        > which way up my data should be and I cannot tell which is correct 
simply by 
        > looking at it!
        > 
        > Many thanks for your time in reading this problem,
        > 
        > Jenny Barnes

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