Just store them as strings in the data frame and then perform a conversion
to expressions prior to the loop:
DF <- data.frame(s = c("O[3]", "NO", "NO[2]"), stringsAsFactors = FALSE)
e <- parse(text = DF$s)
... continue with prior solution ...
On 12/20/06, MrJ Man <[EMAIL PROTECTED]> wrote:
> Thanks for your response; one more thing: Is it
> possible to use a data.frame
> for the same effect, as these values are associated
> with some others (I could
> of course use them separately, but merging them in a
> data.frame should be
> possible in R)?
>
> > Try this:
> >
> >
> > e <- expression(O[3], NO, NO[2])
> > opar <- par(mfrow = c(2,2))
> > for(i in 1:3) plot(1, 1, type = "b", main =
> bquote(.(e[[i]]) ~ Year ~
> > 2005)) par(opar)
> >
> > Also please read the last line to every post to
> r-help and particularly
> > note the part about reproducible examples. x and
> y.were undefined.
> >
>
>
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