try  'regexpr'

> a <- c("apple", "pear")
> regexpr('ear',a)!=-1
[1] FALSE  TRUE
>



On 1/20/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
>
> I'm a relative R novice, and sometimes the simple things trip me up.
>
> Suppose I have
>
> a <- c("apple", "pear")
>
> and I want a logical vector of whether each of these strings contains
> "ear" (in this case, F T). What is the idiom?
>
> Quizzically,
> Mark Lindeman
>
> ______________________________________________
> [email protected] mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

        [[alternative HTML version deleted]]

______________________________________________
[email protected] mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to