Hi Christos,
It's... more or less the same thing. I was looking for a
matrix.to.matrix.run.me() function :)
Cheers,
Adrian
On Sunday 21 January 2007 00:56, Christos Hatzis wrote:
> Here is a slightly more compact version of your function which might run
> faster (I did not test timings) since it does not use the sum:
>
> apply(mat2, 1, function(x) which(apply(mat1, 1, function(y) all(x == y)) ==
> TRUE))
>
> -Christos
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Adrian Dusa
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