Perfect, thxs > -----Original Message----- > From: Dimitris Rizopoulos > [mailto:[EMAIL PROTECTED] > Sent: Wednesday, January 24, 2007 10:49 AM > To: Doran, Harold > Cc: [email protected] > Subject: Re: [R] Replace missing values in lapply > > you need to return x in the function within lapply(), e.g., > something like > > lapply(TP, function(x) { x[is.na(x)] <- 0; x }) > > > I hope it works. > > Best, > Dimitris > > ---- > Dimitris Rizopoulos > Ph.D. Student > Biostatistical Centre > School of Public Health > Catholic University of Leuven > > Address: Kapucijnenvoer 35, Leuven, Belgium > Tel: +32/(0)16/336899 > Fax: +32/(0)16/337015 > Web: http://med.kuleuven.be/biostat/ > http://www.student.kuleuven.be/~m0390867/dimitris.htm > > > > ----- Original Message ----- > From: "Doran, Harold" <[EMAIL PROTECTED]> > To: <[email protected]> > Sent: Wednesday, January 24, 2007 4:40 PM > Subject: [R] Replace missing values in lapply > > > >I have some matrices stored as elements in a list that I am working > > with. On example is provided below as TP[[18]] > > > >> TP[[18]] > > level2 > > level1 1 2 3 4 > > 1 79 0 0 0 > > 2 0 0 0 0 > > 3 0 0 0 0 > > 4 0 0 0 0 > > > > Now, using prop.table on this gives > > > >> prop.table(TP[[18]],1) > > level2 > > level1 1 2 3 4 > > 1 1 0 0 0 > > 2 > > 3 > > 4 > > > > It is important for the zero's to retain their position as this > > matrix > > will subsequently be used in some matrix multiplication and hence, > > must > > be of dimension 4 by 4 so that is it conformable for multiplcation > > with > > another matrix. > > > > In looking at the structure of the object resulting from prop.table > > I > > see NaNs, and so I can do this > > > >> rr <- TP[[18]] > >> rr[is.na(rr)] <- 0 > >> rr > > level2 > > level1 1 2 3 4 > > 1 79 0 0 0 > > 2 0 0 0 0 > > 3 0 0 0 0 > > 4 0 0 0 0 > > > > This is exactly what I want for each matrix. But, I have multiple > > matrices stored within the list that need to be changed and so I am > > trying to resolve this via lapply, but something is awry (namely the > > user), but I could use a little help. > > > > I was thinking the following function should work, but it doesn't. > > It > > reduces each matrix within the list to a 0. > > > > PP <- lapply(TP, function(x) x[is.na(x)] <- 0) > > > > Am I missing something obvious? > > > > Harold > > > > > > [[alternative HTML version deleted]] > > > > ______________________________________________ > > [email protected] mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide > > http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > > > Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm > >
______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
