It occurs why start or stop could not be converted into integer of
length > 0 by using as.interger().
More presicely,
if( !isInteger(sa) || !isInteger(so) || k == 0 || l == 0 ) # c code
where sa is start, so is stop, k is length(start), l is length(stop)
For example:
substr("orz",character(0),0)
substr("orz",numeric(0),0)
substr("orz",logical(0),0)
substr("orz",integer(0),0)
substr("orz",NULL,0)
produce the error because of k==0
But there seems to be another case which I don't know.
On 1/25/07, Shubha Vishwanath Karanth <[EMAIL PROTECTED]> wrote:
> Hi,
>
>
>
> Do anybody know when and why the below error we get?
>
>
>
> Error in substr(x, as.integer(start), as.integer(stop)) :
> invalid substring argument(s) in substr()
>
>
>
> Thanks in advance,
>
> Shubha
>
>
> [[alternative HTML version deleted]]
>
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>
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