a little improvement on ken knoblauch's method by adding the variable n so,
n <- 3 expand.grid(lapply(1:n, function(i) (c(0,1)))) HTH, weiwei On 1/26/07, Zhiliang Ma <[EMAIL PROTECTED]> wrote: > Hi all R users, > I want to create a matrix having n columns and 2^n rows, and all its entries > are only 0 or 1. In each row, column i is 0 means dimension i is chosen, 0 > means not. The matrix will contains all the possible combination of those n > dimensions. > > Here is an example, if n = 3, the matrix will look like: > 0 0 0 > 0 0 1 > 0 1 0 > 1 0 0 > 0 1 1 > 1 0 1 > 1 1 1 > > > I know I can use n "for" loops to do this, but is there a better way? > Thanks, > -zm > > [[alternative HTML version deleted]] > > ______________________________________________ > [email protected] mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Weiwei Shi, Ph.D Research Scientist GeneGO, Inc. "Did you always know?" "No, I did not. But I believed..." ---Matrix III ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
