First question: Yes
Second question: z in func.int2 is z in myfunc (z=y^3).
You can easily test:
f0<-function(){
z<-1
f1<-function()print("f1")
f2<-function(z){f1();print(z)}
f2(z)
}
z<-0
f0()
R language definition may be helpful
http://cran.r-project.org/doc/manuals/R-lang.html#Scope-of-variables
On 1/26/07, domenico pestalozzi <[EMAIL PROTECTED]> wrote:
> If I define my function that includes others "internal functions", how can I
> define the parameter's functions?
> That is:
>
> myfunc<-function(y){...............
>
> func.int1<- function(x){ sum(x}}
> func.int2<-function(z){funct.int1(z)^2} .............................
> }
>
> Is it possible to use func.int1 into func.into2? or R doesn't identify
> func.int1 into func.into2?
>
> Another question:
> If I do
>
> myfunc<-function(y){...............
> z<-y^3
>
> func.int1<- function(x){ sum(x}}
> func.int2<-function(z){z^2}
> .............................
> }
>
> func.int2 is based on z, but now is z=y^3 or a generical object?
>
>
> thanks
>
> pestalozzi
>
> [[alternative HTML version deleted]]
>
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